12(3x-1)=8(3x+1)+40

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Solution for 12(3x-1)=8(3x+1)+40 equation: 



12(3x-1)=8(3x+1)+40

We move all terms to the left:

12(3x-1)-(8(3x+1)+40)=0

We multiply parentheses

36x-(8(3x+1)+40)-12=0



We calculate terms in parentheses: -(8(3x+1)+40), so:

8(3x+1)+40

We multiply parentheses

24x+8+40

We add all the numbers together, and all the variables

24x+48

Back to the equation:

-(24x+48)



We get rid of parentheses

36x-24x-48-12=0

We add all the numbers together, and all the variables

12x-60=0

We move all terms containing x to the left, all other terms to the right

12x=60

x=60/12

x=5

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