12(3x-1)=9(3x+1)+33

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Solution for 12(3x-1)=9(3x+1)+33 equation:



12(3x-1)=9(3x+1)+33
We move all terms to the left:
12(3x-1)-(9(3x+1)+33)=0
We multiply parentheses
36x-(9(3x+1)+33)-12=0
We calculate terms in parentheses: -(9(3x+1)+33), so:
9(3x+1)+33
We multiply parentheses
27x+9+33
We add all the numbers together, and all the variables
27x+42
Back to the equation:
-(27x+42)
We get rid of parentheses
36x-27x-42-12=0
We add all the numbers together, and all the variables
9x-54=0
We move all terms containing x to the left, all other terms to the right
9x=54
x=54/9
x=6

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