12(3x-1)=9(3x+1)+33

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Solution for 12(3x-1)=9(3x+1)+33 equation: 



12(3x-1)=9(3x+1)+33

We move all terms to the left:

12(3x-1)-(9(3x+1)+33)=0

We multiply parentheses

36x-(9(3x+1)+33)-12=0



We calculate terms in parentheses: -(9(3x+1)+33), so:

9(3x+1)+33

We multiply parentheses

27x+9+33

We add all the numbers together, and all the variables

27x+42

Back to the equation:

-(27x+42)



We get rid of parentheses

36x-27x-42-12=0

We add all the numbers together, and all the variables

9x-54=0

We move all terms containing x to the left, all other terms to the right

9x=54

x=54/9

x=6

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