12(3x-2)=32(x+1)

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Solution for 12(3x-2)=32(x+1) equation: 



12(3x-2)=32(x+1)

We move all terms to the left:

12(3x-2)-(32(x+1))=0

We multiply parentheses

36x-(32(x+1))-24=0



We calculate terms in parentheses: -(32(x+1)), so:

32(x+1)

We multiply parentheses

32x+32

Back to the equation:

-(32x+32)



We get rid of parentheses

36x-32x-32-24=0

We add all the numbers together, and all the variables

4x-56=0

We move all terms containing x to the left, all other terms to the right

4x=56

x=56/4

x=14

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