12(3x-5)+11=10(8x-7)-16x

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Solution for 12(3x-5)+11=10(8x-7)-16x equation: 



12(3x-5)+11=10(8x-7)-16x

We move all terms to the left:

12(3x-5)+11-(10(8x-7)-16x)=0

We multiply parentheses

36x-(10(8x-7)-16x)-60+11=0



We calculate terms in parentheses: -(10(8x-7)-16x), so:

10(8x-7)-16x

We add all the numbers together, and all the variables

-16x+10(8x-7)

We multiply parentheses

-16x+80x-70

We add all the numbers together, and all the variables

64x-70

Back to the equation:

-(64x-70)



We add all the numbers together, and all the variables

36x-(64x-70)-49=0

We get rid of parentheses

36x-64x+70-49=0

We add all the numbers together, and all the variables

-28x+21=0

We move all terms containing x to the left, all other terms to the right

-28x=-21

x=-21/-28

x=3/4

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