12(3z+1)=24

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Solution for 12(3z+1)=24 equation: 



12(3z+1)=24

We move all terms to the left:

12(3z+1)-(24)=0

We multiply parentheses

36z+12-24=0

We add all the numbers together, and all the variables

36z-12=0

We move all terms containing z to the left, all other terms to the right

36z=12

z=12/36

z=1/3

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