12(4+v)=-10v+48

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Solution for 12(4+v)=-10v+48 equation: 



12(4+v)=-10v+48

We move all terms to the left:

12(4+v)-(-10v+48)=0

We add all the numbers together, and all the variables

12(v+4)-(-10v+48)=0

We multiply parentheses

12v-(-10v+48)+48=0

We get rid of parentheses

12v+10v-48+48=0

We add all the numbers together, and all the variables

22v=0

v=0/22

v=0

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