12(4+x)=6(12-x)

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Solution for 12(4+x)=6(12-x) equation: 



12(4+x)=6(12-x)

We move all terms to the left:

12(4+x)-(6(12-x))=0

We add all the numbers together, and all the variables

12(x+4)-(6(-1x+12))=0

We multiply parentheses

12x-(6(-1x+12))+48=0



We calculate terms in parentheses: -(6(-1x+12)), so:

6(-1x+12)

We multiply parentheses

-6x+72

Back to the equation:

-(-6x+72)



We get rid of parentheses

12x+6x-72+48=0

We add all the numbers together, and all the variables

18x-24=0

We move all terms containing x to the left, all other terms to the right

18x=24

x=24/18

x=1+1/3

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