12(4b+6)=15+2b

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Solution for 12(4b+6)=15+2b equation: 



12(4b+6)=15+2b

We move all terms to the left:

12(4b+6)-(15+2b)=0

We add all the numbers together, and all the variables

12(4b+6)-(2b+15)=0

We multiply parentheses

48b-(2b+15)+72=0

We get rid of parentheses

48b-2b-15+72=0

We add all the numbers together, and all the variables

46b+57=0

We move all terms containing b to the left, all other terms to the right

46b=-57

b=-57/46

b=-1+11/46

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