12(4x+)=3(x+5)+(3x-3)

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Solution for 12(4x+)=3(x+5)+(3x-3) equation: 



12(4x+)=3(x+5)+(3x-3)

We move all terms to the left:

12(4x+)-(3(x+5)+(3x-3))=0

We add all the numbers together, and all the variables

12(+4x)-(3(x+5)+(3x-3))=0

We multiply parentheses

48x-(3(x+5)+(3x-3))=0



We calculate terms in parentheses: -(3(x+5)+(3x-3)), so:

3(x+5)+(3x-3)

We multiply parentheses

3x+(3x-3)+15

We get rid of parentheses

3x+3x-3+15

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

48x-6x-12=0

We add all the numbers together, and all the variables

42x-12=0

We move all terms containing x to the left, all other terms to the right

42x=12

x=12/42

x=2/7

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