12(4x-5x/6)+20=19x-15+45x/2

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Solution for 12(4x-5x/6)+20=19x-15+45x/2 equation:



12(4x-5x/6)+20=19x-15+45x/2
We move all terms to the left:
12(4x-5x/6)+20-(19x-15+45x/2)=0
We add all the numbers together, and all the variables
12(+4x-5x/6)-(19x+45x/2-15)+20=0
We multiply parentheses
48x-60x-(19x+45x/2-15)+20=0
We get rid of parentheses
48x-60x-19x-45x/2+15+20=0
We multiply all the terms by the denominator
48x*2-60x*2-19x*2-45x+15*2+20*2=0
We add all the numbers together, and all the variables
-45x+48x*2-60x*2-19x*2+70=0
Wy multiply elements
-45x+96x-120x-38x+70=0
We add all the numbers together, and all the variables
-107x+70=0
We move all terms containing x to the left, all other terms to the right
-107x=-70
x=-70/-107
x=70/107

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