12(4y+4)=y-6

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Solution for 12(4y+4)=y-6 equation: 



12(4y+4)=y-6

We move all terms to the left:

12(4y+4)-(y-6)=0

We multiply parentheses

48y-(y-6)+48=0

We get rid of parentheses

48y-y+6+48=0

We add all the numbers together, and all the variables

47y+54=0

We move all terms containing y to the left, all other terms to the right

47y=-54

y=-54/47

y=-1+7/47

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