12(5c-1)-10=58c+12

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Solution for 12(5c-1)-10=58c+12 equation: 



12(5c-1)-10=58c+12

We move all terms to the left:

12(5c-1)-10-(58c+12)=0

We multiply parentheses

60c-(58c+12)-12-10=0

We get rid of parentheses

60c-58c-12-12-10=0

We add all the numbers together, and all the variables

2c-34=0

We move all terms containing c to the left, all other terms to the right

2c=34

c=34/2

c=17

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