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12*((5*x)/4-x)^12*(x/12-(4/3)) = 0
12*((5*x)/4-x)^12*(x/12-4/3) = 0
12*(1/4*x)^12*(1/12*x-4/3) = 0
( 1/12*x-4/3 )
1/12*x-4/3 = 0 // + 4/3
1/12*x = 4/3 // : 1/12
x = 4/3/1/12
x = 16
( 1/4*x )
1/4*x = 0 // : 1/4
x = 0
x in { 16, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }
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