12(6+4m)+8m=2(9m-2)

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Solution for 12(6+4m)+8m=2(9m-2) equation: 



12(6+4m)+8m=2(9m-2)

We move all terms to the left:

12(6+4m)+8m-(2(9m-2))=0

We add all the numbers together, and all the variables

12(4m+6)+8m-(2(9m-2))=0

We add all the numbers together, and all the variables

8m+12(4m+6)-(2(9m-2))=0

We multiply parentheses

8m+48m-(2(9m-2))+72=0



We calculate terms in parentheses: -(2(9m-2)), so:

2(9m-2)

We multiply parentheses

18m-4

Back to the equation:

-(18m-4)



We add all the numbers together, and all the variables

56m-(18m-4)+72=0

We get rid of parentheses

56m-18m+4+72=0

We add all the numbers together, and all the variables

38m+76=0

We move all terms containing m to the left, all other terms to the right

38m=-76

m=-76/38

m=-2

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