12(6x-4)=3(x-2)

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Solution for 12(6x-4)=3(x-2) equation: 



12(6x-4)=3(x-2)

We move all terms to the left:

12(6x-4)-(3(x-2))=0

We multiply parentheses

72x-(3(x-2))-48=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

72x-3x+6-48=0

We add all the numbers together, and all the variables

69x-42=0

We move all terms containing x to the left, all other terms to the right

69x=42

x=42/69

x=14/23

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