12(6y-4)=2y+10

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Solution for 12(6y-4)=2y+10 equation: 



12(6y-4)=2y+10

We move all terms to the left:

12(6y-4)-(2y+10)=0

We multiply parentheses

72y-(2y+10)-48=0

We get rid of parentheses

72y-2y-10-48=0

We add all the numbers together, and all the variables

70y-58=0

We move all terms containing y to the left, all other terms to the right

70y=58

y=58/70

y=29/35

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