12(9c-1)-18=106c+12

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Solution for 12(9c-1)-18=106c+12 equation: 



12(9c-1)-18=106c+12

We move all terms to the left:

12(9c-1)-18-(106c+12)=0

We multiply parentheses

108c-(106c+12)-12-18=0

We get rid of parentheses

108c-106c-12-12-18=0

We add all the numbers together, and all the variables

2c-42=0

We move all terms containing c to the left, all other terms to the right

2c=42

c=42/2

c=21

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