12(Z/2+4)=10z-40

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Solution for 12(Z/2+4)=10z-40 equation: 



12(/2+4)=10Z-40

We move all terms to the left:

12(/2+4)-(10Z-40)=0

We multiply parentheses

-(10Z-40)+48+/2*12=0

We get rid of parentheses

-10Z+40+48+/2*12=0

We multiply all the terms by the denominator


-10Z*2*12+40*2*12+48*2*12+=0

We add all the numbers together, and all the variables

-10Z*2*12=0

Wy multiply elements

-240Z*1=0

Wy multiply elements

-240Z=0

Z=0/-240

Z=0

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