12(a+b+c)=

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Solution for 12(a+b+c)= equation:


Simplifying
12(a + b + c) = 0
(a * 12 + b * 12 + c * 12) = 0
(12a + 12b + 12c) = 0

Solving
12a + 12b + 12c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-12b' to each side of the equation.
12a + 12b + -12b + 12c = 0 + -12b

Combine like terms: 12b + -12b = 0
12a + 0 + 12c = 0 + -12b
12a + 12c = 0 + -12b
Remove the zero:
12a + 12c = -12b

Add '-12c' to each side of the equation.
12a + 12c + -12c = -12b + -12c

Combine like terms: 12c + -12c = 0
12a + 0 = -12b + -12c
12a = -12b + -12c

Divide each side by '12'.
a = -1b + -1c

Simplifying
a = -1b + -1c

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