12(b+12)+6=9(b-2)+9

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Solution for 12(b+12)+6=9(b-2)+9 equation: 



12(b+12)+6=9(b-2)+9

We move all terms to the left:

12(b+12)+6-(9(b-2)+9)=0

We multiply parentheses

12b-(9(b-2)+9)+144+6=0



We calculate terms in parentheses: -(9(b-2)+9), so:

9(b-2)+9

We multiply parentheses

9b-18+9

We add all the numbers together, and all the variables

9b-9

Back to the equation:

-(9b-9)



We add all the numbers together, and all the variables

12b-(9b-9)+150=0

We get rid of parentheses

12b-9b+9+150=0

We add all the numbers together, and all the variables

3b+159=0

We move all terms containing b to the left, all other terms to the right

3b=-159

b=-159/3

b=-53

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