12(b+2)=6(b+5)

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Solution for 12(b+2)=6(b+5) equation: 



12(b+2)=6(b+5)

We move all terms to the left:

12(b+2)-(6(b+5))=0

We multiply parentheses

12b-(6(b+5))+24=0



We calculate terms in parentheses: -(6(b+5)), so:

6(b+5)

We multiply parentheses

6b+30

Back to the equation:

-(6b+30)



We get rid of parentheses

12b-6b-30+24=0

We add all the numbers together, and all the variables

6b-6=0

We move all terms containing b to the left, all other terms to the right

6b=6

b=6/6

b=1

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