12(b+2)=8(b-5)

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Solution for 12(b+2)=8(b-5) equation:



12(b+2)=8(b-5)
We move all terms to the left:
12(b+2)-(8(b-5))=0
We multiply parentheses
12b-(8(b-5))+24=0
We calculate terms in parentheses: -(8(b-5)), so:
8(b-5)
We multiply parentheses
8b-40
Back to the equation:
-(8b-40)
We get rid of parentheses
12b-8b+40+24=0
We add all the numbers together, and all the variables
4b+64=0
We move all terms containing b to the left, all other terms to the right
4b=-64
b=-64/4
b=-16

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