12(b+3)=4(3b+3)+3b

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Solution for 12(b+3)=4(3b+3)+3b equation:


Simplifying
12(b + 3) = 4(3b + 3) + 3b

Reorder the terms:
12(3 + b) = 4(3b + 3) + 3b
(3 * 12 + b * 12) = 4(3b + 3) + 3b
(36 + 12b) = 4(3b + 3) + 3b

Reorder the terms:
36 + 12b = 4(3 + 3b) + 3b
36 + 12b = (3 * 4 + 3b * 4) + 3b
36 + 12b = (12 + 12b) + 3b

Combine like terms: 12b + 3b = 15b
36 + 12b = 12 + 15b

Solving
36 + 12b = 12 + 15b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-15b' to each side of the equation.
36 + 12b + -15b = 12 + 15b + -15b

Combine like terms: 12b + -15b = -3b
36 + -3b = 12 + 15b + -15b

Combine like terms: 15b + -15b = 0
36 + -3b = 12 + 0
36 + -3b = 12

Add '-36' to each side of the equation.
36 + -36 + -3b = 12 + -36

Combine like terms: 36 + -36 = 0
0 + -3b = 12 + -36
-3b = 12 + -36

Combine like terms: 12 + -36 = -24
-3b = -24

Divide each side by '-3'.
b = 8

Simplifying
b = 8

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