12(b-3)-5b=4(2b+3)

Solution for 12(b-3)-5b=4(2b+3) equation:

12(b-3)-5b=4(2b+3)

We move all terms to the left:

12(b-3)-5b-(4(2b+3))=0

We add all the numbers together, and all the variables

-5b+12(b-3)-(4(2b+3))=0

We multiply parentheses

-5b+12b-(4(2b+3))-36=0


We calculate terms in parentheses: -(4(2b+3)), so:

4(2b+3)

We multiply parentheses

8b+12

Back to the equation:

-(8b+12)


We add all the numbers together, and all the variables

7b-(8b+12)-36=0

We get rid of parentheses

7b-8b-12-36=0

We add all the numbers together, and all the variables

-1b-48=0

We move all terms containing b to the left, all other terms to the right

-b=48

b=48/-1

b=-48