12(b-3)=12(b+10)+2

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Solution for 12(b-3)=12(b+10)+2 equation:


Simplifying
12(b + -3) = 12(b + 10) + 2

Reorder the terms:
12(-3 + b) = 12(b + 10) + 2
(-3 * 12 + b * 12) = 12(b + 10) + 2
(-36 + 12b) = 12(b + 10) + 2

Reorder the terms:
-36 + 12b = 12(10 + b) + 2
-36 + 12b = (10 * 12 + b * 12) + 2
-36 + 12b = (120 + 12b) + 2

Reorder the terms:
-36 + 12b = 120 + 2 + 12b

Combine like terms: 120 + 2 = 122
-36 + 12b = 122 + 12b

Add '-12b' to each side of the equation.
-36 + 12b + -12b = 122 + 12b + -12b

Combine like terms: 12b + -12b = 0
-36 + 0 = 122 + 12b + -12b
-36 = 122 + 12b + -12b

Combine like terms: 12b + -12b = 0
-36 = 122 + 0
-36 = 122

Solving
-36 = 122

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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