12(b-7)=-(1-3b)

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Solution for 12(b-7)=-(1-3b) equation: 



12(b-7)=-(1-3b)

We move all terms to the left:

12(b-7)-(-(1-3b))=0

We add all the numbers together, and all the variables

12(b-7)-(-(-3b+1))=0

We multiply parentheses

12b-(-(-3b+1))-84=0



We calculate terms in parentheses: -(-(-3b+1)), so:

-(-3b+1)

We get rid of parentheses

3b-1

Back to the equation:

-(3b-1)



We get rid of parentheses

12b-3b+1-84=0

We add all the numbers together, and all the variables

9b-83=0

We move all terms containing b to the left, all other terms to the right

9b=83

b=83/9

b=9+2/9

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