12(c+3)-30=2(6c+18)

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Solution for 12(c+3)-30=2(6c+18) equation:


Simplifying
12(c + 3) + -30 = 2(6c + 18)

Reorder the terms:
12(3 + c) + -30 = 2(6c + 18)
(3 * 12 + c * 12) + -30 = 2(6c + 18)
(36 + 12c) + -30 = 2(6c + 18)

Reorder the terms:
36 + -30 + 12c = 2(6c + 18)

Combine like terms: 36 + -30 = 6
6 + 12c = 2(6c + 18)

Reorder the terms:
6 + 12c = 2(18 + 6c)
6 + 12c = (18 * 2 + 6c * 2)
6 + 12c = (36 + 12c)

Add '-12c' to each side of the equation.
6 + 12c + -12c = 36 + 12c + -12c

Combine like terms: 12c + -12c = 0
6 + 0 = 36 + 12c + -12c
6 = 36 + 12c + -12c

Combine like terms: 12c + -12c = 0
6 = 36 + 0
6 = 36

Solving
6 = 36

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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