12(c+5)-46=2(6c+7)

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Solution for 12(c+5)-46=2(6c+7) equation: 



12(c+5)-46=2(6c+7)

We move all terms to the left:

12(c+5)-46-(2(6c+7))=0

We multiply parentheses

12c-(2(6c+7))+60-46=0



We calculate terms in parentheses: -(2(6c+7)), so:

2(6c+7)

We multiply parentheses

12c+14

Back to the equation:

-(12c+14)



We add all the numbers together, and all the variables

12c-(12c+14)+14=0

We get rid of parentheses

12c-12c-14+14=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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