12(c-7)+6=12+2c

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Solution for 12(c-7)+6=12+2c equation: 



12(c-7)+6=12+2c

We move all terms to the left:

12(c-7)+6-(12+2c)=0

We add all the numbers together, and all the variables

12(c-7)-(2c+12)+6=0

We multiply parentheses

12c-(2c+12)-84+6=0

We get rid of parentheses

12c-2c-12-84+6=0

We add all the numbers together, and all the variables

10c-90=0

We move all terms containing c to the left, all other terms to the right

10c=90

c=90/10

c=9

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