12(d+2)=4(d-6)+8d

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Solution for 12(d+2)=4(d-6)+8d equation: 



12(d+2)=4(d-6)+8d

We move all terms to the left:

12(d+2)-(4(d-6)+8d)=0

We multiply parentheses

12d-(4(d-6)+8d)+24=0



We calculate terms in parentheses: -(4(d-6)+8d), so:

4(d-6)+8d

We add all the numbers together, and all the variables

8d+4(d-6)

We multiply parentheses

8d+4d-24

We add all the numbers together, and all the variables

12d-24

Back to the equation:

-(12d-24)



We get rid of parentheses

12d-12d+24+24=0

We add all the numbers together, and all the variables

48!=0

There is no solution for this equation

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