12(d+4)=3(d-4)+9d

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Solution for 12(d+4)=3(d-4)+9d equation: 



12(d+4)=3(d-4)+9d

We move all terms to the left:

12(d+4)-(3(d-4)+9d)=0

We multiply parentheses

12d-(3(d-4)+9d)+48=0



We calculate terms in parentheses: -(3(d-4)+9d), so:

3(d-4)+9d

We add all the numbers together, and all the variables

9d+3(d-4)

We multiply parentheses

9d+3d-12

We add all the numbers together, and all the variables

12d-12

Back to the equation:

-(12d-12)



We get rid of parentheses

12d-12d+12+48=0

We add all the numbers together, and all the variables

60!=0

There is no solution for this equation

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