12(m+5)-42=3(4m+6)

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Solution for 12(m+5)-42=3(4m+6) equation: 



12(m+5)-42=3(4m+6)

We move all terms to the left:

12(m+5)-42-(3(4m+6))=0

We multiply parentheses

12m-(3(4m+6))+60-42=0



We calculate terms in parentheses: -(3(4m+6)), so:

3(4m+6)

We multiply parentheses

12m+18

Back to the equation:

-(12m+18)



We add all the numbers together, and all the variables

12m-(12m+18)+18=0

We get rid of parentheses

12m-12m-18+18=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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