12(n+1)=8(n-5)

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Solution for 12(n+1)=8(n-5) equation: 



12(n+1)=8(n-5)

We move all terms to the left:

12(n+1)-(8(n-5))=0

We multiply parentheses

12n-(8(n-5))+12=0



We calculate terms in parentheses: -(8(n-5)), so:

8(n-5)

We multiply parentheses

8n-40

Back to the equation:

-(8n-40)



We get rid of parentheses

12n-8n+40+12=0

We add all the numbers together, and all the variables

4n+52=0

We move all terms containing n to the left, all other terms to the right

4n=-52

n=-52/4

n=-13

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