12(n+3)=4(2n+9)+4n

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Solution for 12(n+3)=4(2n+9)+4n equation: 


Simplifying
12(n + 3) = 4(2n + 9) + 4n

Reorder the terms:
12(3 + n) = 4(2n + 9) + 4n
(3 * 12 + n * 12) = 4(2n + 9) + 4n
(36 + 12n) = 4(2n + 9) + 4n

Reorder the terms:
36 + 12n = 4(9 + 2n) + 4n
36 + 12n = (9 * 4 + 2n * 4) + 4n
36 + 12n = (36 + 8n) + 4n

Combine like terms: 8n + 4n = 12n
36 + 12n = 36 + 12n

Add '-36' to each side of the equation.
36 + -36 + 12n = 36 + -36 + 12n

Combine like terms: 36 + -36 = 0
0 + 12n = 36 + -36 + 12n
12n = 36 + -36 + 12n

Combine like terms: 36 + -36 = 0
12n = 0 + 12n
12n = 12n

Add '-12n' to each side of the equation.
12n + -12n = 12n + -12n

Combine like terms: 12n + -12n = 0
0 = 12n + -12n

Combine like terms: 12n + -12n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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