12(n+4)=3(16+4n)

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Solution for 12(n+4)=3(16+4n) equation: 


Simplifying
12(n + 4) = 3(16 + 4n)

Reorder the terms:
12(4 + n) = 3(16 + 4n)
(4 * 12 + n * 12) = 3(16 + 4n)
(48 + 12n) = 3(16 + 4n)
48 + 12n = (16 * 3 + 4n * 3)
48 + 12n = (48 + 12n)

Add '-48' to each side of the equation.
48 + -48 + 12n = 48 + -48 + 12n

Combine like terms: 48 + -48 = 0
0 + 12n = 48 + -48 + 12n
12n = 48 + -48 + 12n

Combine like terms: 48 + -48 = 0
12n = 0 + 12n
12n = 12n

Add '-12n' to each side of the equation.
12n + -12n = 12n + -12n

Combine like terms: 12n + -12n = 0
0 = 12n + -12n

Combine like terms: 12n + -12n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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