12(n+5)=3(20+4n)

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Solution for 12(n+5)=3(20+4n) equation: 


Simplifying
12(n + 5) = 3(20 + 4n)

Reorder the terms:
12(5 + n) = 3(20 + 4n)
(5 * 12 + n * 12) = 3(20 + 4n)
(60 + 12n) = 3(20 + 4n)
60 + 12n = (20 * 3 + 4n * 3)
60 + 12n = (60 + 12n)

Add '-60' to each side of the equation.
60 + -60 + 12n = 60 + -60 + 12n

Combine like terms: 60 + -60 = 0
0 + 12n = 60 + -60 + 12n
12n = 60 + -60 + 12n

Combine like terms: 60 + -60 = 0
12n = 0 + 12n
12n = 12n

Add '-12n' to each side of the equation.
12n + -12n = 12n + -12n

Combine like terms: 12n + -12n = 0
0 = 12n + -12n

Combine like terms: 12n + -12n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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