12(n-1)+3n=4n-4

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Solution for 12(n-1)+3n=4n-4 equation: 



12(n-1)+3n=4n-4

We move all terms to the left:

12(n-1)+3n-(4n-4)=0

We add all the numbers together, and all the variables

3n+12(n-1)-(4n-4)=0

We multiply parentheses

3n+12n-(4n-4)-12=0

We get rid of parentheses

3n+12n-4n+4-12=0

We add all the numbers together, and all the variables

11n-8=0

We move all terms containing n to the left, all other terms to the right

11n=8

n=8/11

n=8/11

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