12(n-1)+9=4(n+2)-3

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Solution for 12(n-1)+9=4(n+2)-3 equation:



12(n-1)+9=4(n+2)-3
We move all terms to the left:
12(n-1)+9-(4(n+2)-3)=0
We multiply parentheses
12n-(4(n+2)-3)-12+9=0
We calculate terms in parentheses: -(4(n+2)-3), so:
4(n+2)-3
We multiply parentheses
4n+8-3
We add all the numbers together, and all the variables
4n+5
Back to the equation:
-(4n+5)
We add all the numbers together, and all the variables
12n-(4n+5)-3=0
We get rid of parentheses
12n-4n-5-3=0
We add all the numbers together, and all the variables
8n-8=0
We move all terms containing n to the left, all other terms to the right
8n=8
n=8/8
n=1

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