12(n-20)=-40

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Solution for 12(n-20)=-40 equation: 



12(n-20)=-40

We move all terms to the left:

12(n-20)-(-40)=0

We add all the numbers together, and all the variables

12(n-20)+40=0

We multiply parentheses

12n-240+40=0

We add all the numbers together, and all the variables

12n-200=0

We move all terms containing n to the left, all other terms to the right

12n=200

n=200/12

n=16+2/3

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