12(p-4)=(6p+10)

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Solution for 12(p-4)=(6p+10) equation: 



12(p-4)=(6p+10)

We move all terms to the left:

12(p-4)-((6p+10))=0

We multiply parentheses

12p-((6p+10))-48=0



We calculate terms in parentheses: -((6p+10)), so:

(6p+10)

We get rid of parentheses

6p+10

Back to the equation:

-(6p+10)



We get rid of parentheses

12p-6p-10-48=0

We add all the numbers together, and all the variables

6p-58=0

We move all terms containing p to the left, all other terms to the right

6p=58

p=58/6

p=9+2/3

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