12(r+3)=2r+10-3r

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Solution for 12(r+3)=2r+10-3r equation: 



12(r+3)=2r+10-3r

We move all terms to the left:

12(r+3)-(2r+10-3r)=0

We add all the numbers together, and all the variables

12(r+3)-(-1r+10)=0

We multiply parentheses

12r-(-1r+10)+36=0

We get rid of parentheses

12r+1r-10+36=0

We add all the numbers together, and all the variables

13r+26=0

We move all terms containing r to the left, all other terms to the right

13r=-26

r=-26/13

r=-2

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