12(r+5)=2(r+5)-3r

Solution for 12(r+5)=2(r+5)-3r equation:

12(r+5)=2(r+5)-3r

We move all terms to the left:

12(r+5)-(2(r+5)-3r)=0

We multiply parentheses

12r-(2(r+5)-3r)+60=0


We calculate terms in parentheses: -(2(r+5)-3r), so:

2(r+5)-3r

We add all the numbers together, and all the variables

-3r+2(r+5)

We multiply parentheses

-3r+2r+10

We add all the numbers together, and all the variables

-1r+10

Back to the equation:

-(-1r+10)


We get rid of parentheses

12r+1r-10+60=0

We add all the numbers together, and all the variables

13r+50=0

We move all terms containing r to the left, all other terms to the right

13r=-50

r=-50/13

r=-3+11/13