12(t-1)=8(t+2)-t

Solution for 12(t-1)=8(t+2)-t equation:

12(t-1)=8(t+2)-t

We move all terms to the left:

12(t-1)-(8(t+2)-t)=0

We multiply parentheses

12t-(8(t+2)-t)-12=0


We calculate terms in parentheses: -(8(t+2)-t), so:

8(t+2)-t

We add all the numbers together, and all the variables

-1t+8(t+2)

We multiply parentheses

-1t+8t+16

We add all the numbers together, and all the variables

7t+16

Back to the equation:

-(7t+16)


We get rid of parentheses

12t-7t-16-12=0

We add all the numbers together, and all the variables

5t-28=0

We move all terms containing t to the left, all other terms to the right

5t=28

t=28/5

t=5+3/5