12(t-2)+6t=6(3t+3)-11

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Solution for 12(t-2)+6t=6(3t+3)-11 equation: 



12(t-2)+6t=6(3t+3)-11

We move all terms to the left:

12(t-2)+6t-(6(3t+3)-11)=0

We add all the numbers together, and all the variables

6t+12(t-2)-(6(3t+3)-11)=0

We multiply parentheses

6t+12t-(6(3t+3)-11)-24=0



We calculate terms in parentheses: -(6(3t+3)-11), so:

6(3t+3)-11

We multiply parentheses

18t+18-11

We add all the numbers together, and all the variables

18t+7

Back to the equation:

-(18t+7)



We add all the numbers together, and all the variables

18t-(18t+7)-24=0

We get rid of parentheses

18t-18t-7-24=0

We add all the numbers together, and all the variables

-31!=0

There is no solution for this equation

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