12(t-3)+1=6-(t-1)-5

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Solution for 12(t-3)+1=6-(t-1)-5 equation: 



12(t-3)+1=6-(t-1)-5

We move all terms to the left:

12(t-3)+1-(6-(t-1)-5)=0

We multiply parentheses

12t-(6-(t-1)-5)-36+1=0



We calculate terms in parentheses: -(6-(t-1)-5), so:

6-(t-1)-5

determiningTheFunctionDomain
-(t-1)+6-5

We add all the numbers together, and all the variables

-(t-1)+1

We get rid of parentheses

-t+1+1

We add all the numbers together, and all the variables

-1t+2

Back to the equation:

-(-1t+2)



We add all the numbers together, and all the variables

12t-(-1t+2)-35=0

We get rid of parentheses

12t+1t-2-35=0

We add all the numbers together, and all the variables

13t-37=0

We move all terms containing t to the left, all other terms to the right

13t=37

t=37/13

t=2+11/13

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