12(t-4)+6t=6(3t+3)-10

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Solution for 12(t-4)+6t=6(3t+3)-10 equation: 



12(t-4)+6t=6(3t+3)-10

We move all terms to the left:

12(t-4)+6t-(6(3t+3)-10)=0

We add all the numbers together, and all the variables

6t+12(t-4)-(6(3t+3)-10)=0

We multiply parentheses

6t+12t-(6(3t+3)-10)-48=0



We calculate terms in parentheses: -(6(3t+3)-10), so:

6(3t+3)-10

We multiply parentheses

18t+18-10

We add all the numbers together, and all the variables

18t+8

Back to the equation:

-(18t+8)



We add all the numbers together, and all the variables

18t-(18t+8)-48=0

We get rid of parentheses

18t-18t-8-48=0

We add all the numbers together, and all the variables

-56!=0

There is no solution for this equation

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