12(t-4)+6t=6(3t+3)-8

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Solution for 12(t-4)+6t=6(3t+3)-8 equation: 



12(t-4)+6t=6(3t+3)-8

We move all terms to the left:

12(t-4)+6t-(6(3t+3)-8)=0

We add all the numbers together, and all the variables

6t+12(t-4)-(6(3t+3)-8)=0

We multiply parentheses

6t+12t-(6(3t+3)-8)-48=0



We calculate terms in parentheses: -(6(3t+3)-8), so:

6(3t+3)-8

We multiply parentheses

18t+18-8

We add all the numbers together, and all the variables

18t+10

Back to the equation:

-(18t+10)



We add all the numbers together, and all the variables

18t-(18t+10)-48=0

We get rid of parentheses

18t-18t-10-48=0

We add all the numbers together, and all the variables

-58!=0

There is no solution for this equation

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