12(t-4)=10-2t

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Solution for 12(t-4)=10-2t equation: 



12(t-4)=10-2t

We move all terms to the left:

12(t-4)-(10-2t)=0

We add all the numbers together, and all the variables

12(t-4)-(-2t+10)=0

We multiply parentheses

12t-(-2t+10)-48=0

We get rid of parentheses

12t+2t-10-48=0

We add all the numbers together, and all the variables

14t-58=0

We move all terms containing t to the left, all other terms to the right

14t=58

t=58/14

t=4+1/7

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