12(v+1)=-6v+3(6+4v)

Solution for 12(v+1)=-6v+3(6+4v) equation:

12(v+1)=-6v+3(6+4v)

We move all terms to the left:

12(v+1)-(-6v+3(6+4v))=0

We add all the numbers together, and all the variables

12(v+1)-(-6v+3(4v+6))=0

We multiply parentheses

12v-(-6v+3(4v+6))+12=0


We calculate terms in parentheses: -(-6v+3(4v+6)), so:

-6v+3(4v+6)

We multiply parentheses

-6v+12v+18

We add all the numbers together, and all the variables

6v+18

Back to the equation:

-(6v+18)


We get rid of parentheses

12v-6v-18+12=0

We add all the numbers together, and all the variables

6v-6=0

We move all terms containing v to the left, all other terms to the right

6v=6

v=6/6

v=1