12(v+2)-4v=4(2v+4)-23

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Solution for 12(v+2)-4v=4(2v+4)-23 equation: 



12(v+2)-4v=4(2v+4)-23

We move all terms to the left:

12(v+2)-4v-(4(2v+4)-23)=0

We add all the numbers together, and all the variables

-4v+12(v+2)-(4(2v+4)-23)=0

We multiply parentheses

-4v+12v-(4(2v+4)-23)+24=0



We calculate terms in parentheses: -(4(2v+4)-23), so:

4(2v+4)-23

We multiply parentheses

8v+16-23

We add all the numbers together, and all the variables

8v-7

Back to the equation:

-(8v-7)



We add all the numbers together, and all the variables

8v-(8v-7)+24=0

We get rid of parentheses

8v-8v+7+24=0

We add all the numbers together, and all the variables

31!=0

There is no solution for this equation

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